3.5 eigrp bw and dly table

dly and bw eigrp

http://blogs.interfacett.com/ciscos-eigrp-metric-fact-and-not-so-fact

the above is an excellent explanation of this tricky subject.

reduction:

METRIC=256∗[( k1∗bandwidth) + (k3∗delay)]

or better yet

METRIC=256∗(BW+Delay)

FastEthernet0/0 is up, line protocol is up
Hardware is AmdFE, address is cc01.0bb4.0000 (bia cc01.0bb4.0000)
Internet address is 192.168.16.1/24
MTU 1500 bytes, BW 100000 Kbit, DLY 100 usec,

R1#sh int lo0
Loopback0 is up, line protocol is up
Hardware is Loopback
Internet address is 10.10.10.10/24
MTU 1514 bytes, BW 8000000 Kbit, DLY 5000 usec,

R1#sh int s3/0
Serial3/0 is up, line protocol is up
Hardware is M4T
Internet address is 172.20.15.2/30
MTU 1500 bytes, BW 1544 Kbit, DLY 20000 usec,

and this excellent article from:

https://learningnetwork.cisco.com/docs/DOC-13825

EIGRP_Metric_Calculation_Demystified

http://www.cisco.com/c/en/us/support/docs/ip/enhanced-interior-gateway-routing-protocol-eigrp/16406-eigrp-toc.pdf

metric = 10^7 (10000000) divided by least bandwidth along the given path + cumulative delay along the path times 256